1 + 1/2 + 1/3 + 1/4 + 1/5 … 1/n terms.
#include<stdio.h>
int main()
{
int i, n;
float sum=0;
printf("Enter limit : ");
scanf("%d",&n);
printf("%d",1);
for(i=2;i<=n;i++)
{
printf("+%d/%d", 1,i);
}
for(i=1;i<=n;i++)
{
sum = sum + 1/(float)i;
}
printf(" = %f\n",sum);
return 0;
}